y^2-55y+600=0

Solution for y^2-55y+600=0 equation:

y^2-55y+600=0

a = 1; b = -55; c = +600;
Δ = b2-4ac
Δ = -552-4·1·600
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-25}{2*1}=\frac{30}{2}
=15
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+25}{2*1}=\frac{80}{2}
=40
$